Question

公共类六氧化color {

public static void main(String[] args) {
    String a="0x5b9f18";
    String hexColor = String.format("#%06X", a);
    System.out.println(hexColor);
时 时

时时

信件错误

Exception in thread "main" java.util.IllegalFormatConversionException: x != java.lang.String at java.util.Formatter$FormatSpecifier.failConversion(Unknown Source) at java.util.Formatter$FormatSpecifier.printInteger(Unknown Source) at java.util.Formatter$FormatSpecifier.print(Unknown Source) at java.util.Formatter.format(Unknown Source) at java.util.Formatter.format(Unknown Source) at java.lang.String.format(Unknown Source) at Hexcolor.main(Hexcolor.java:6)

Answer 1

不知道你要求的是什么...

public static void main(String[] args) {
  int a = 0x5b9f18;
  String hexCol或= String.format("#%06X", a);
  System.out.println(hexColor);
}

或

public static void main(String[] args) {
   String a="0x5b9f18";
   String hexCol或= "#" + a.substring(2);
   System.out.println(hexColor);
}

友情链接