似乎我有一个奇怪的问题。 我将创建一个选择的菜单, 并将其指派给某个名为选中菜单的插件
$( #selectCombo ).selectmenu({style: dropdown });
在指派给它之后, 我无法隐藏它, 或按选择设置选项 。 我尝试了这个
$( <option value= +ret.cId+ selected=true> +ret.cName+ </option> ).appendTo( #selectCombo );
$( #selectCombo ).selectmenu({style: dropdown });
它在工作, 但是它正在显示另一例下方的 dopdown 实例 。 我试图删除类属性, 但是它没有起作用 。 有办法帮助吗 。 plz 帮助 。 @ plz help
Custom 选择菜单 通常会创建
这意味着自定义的选定菜单不会知道您对 原始 lt; select> 所做的更改 。
呼叫 .selectmenu( 销毁) 之前先拨打 < code>. selectmenu( { 风格: 下调) ; again.
<强 > e.
var newOption = $( <option value= +ret.cId+ selected=true> +ret.cName+ </option> );
$( #selectCombo ).append(newOption).selectmenu( destroy ).selectmenu({style: dropdown });
http://jsfidd.net/3B3Fp/" rel="notfollow" 举个例子。
您可以通过跟随隐藏
$( #selectCombo ).next( .ui-selectmenu .ui-selectmenu-button ).hide();
并设置选定选项使用此选项。
var value = <your value to select>;
$( #selectCombo ).selectmenu("value", value);
var value = "anyvalue";
$("#selectboxid").val("value");
""http://jsfiddle.net/anupam/GGJ7w/" rel="nofollow" > check this
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