Question

我用 jQueryMobile 设计一个 PhoneGap 应用程序。在我的应用程序中, 我每四分钟需要发送一个用户当前地理定位 GPS 坐标到服务器。我该怎么做?

这是我一直在使用的代码, 但它没有发送任何数据。我怎样才能修改这个来让它生效?

document.addEventListener("deviceready", onDeviceReady, false);

var watchID = null;

// PhoneGap is ready
//
function onDeviceReady() {
    // Update every 4 minute
    var options = { maximumAge: 240000, timeout: 5000, enableHighAccuracy: true };
    watchID = navigator.geolocation.watchPosition(onSuccess, onError, options);
}

// onSuccess Geolocation
//
function onSuccess(position) {
   var lat = Position.coords.latitude;
    var lng = Position.coords.longitude;


    jQuery.ajax({
        type: "POST", 
        url:  serviceURL+"locationUpdate.php", 
        data:  x= +lng+ &y= +lat,
        cache: false
    });
}

// onError Callback receives a PositionError object
//
function onError(error) {
    alert( code:      + error.code    +  
  +
           message:   + error.message +  
 );
}

Answer 1

而不是打电话给Interval, 让电话gap做给你。

// onSuccess Callback
//   This method accepts a `Position` object, which contains the current GPS coordinates
//
function onSuccess(position) {
    var element = document.getElementById( geolocation );
    element.innerHTML =  Latitude:    + position.coords.latitude      +  <br />  +
                     Longitude:   + position.coords.longitude     +  <br />  +
                     <hr />       + element.innerHTML;
}

// onError Callback receives a PositionError object
//
function onError(error) {
    alert( code:      + error.code    +  
  +
       message:   + error.message +  
 );
}

// Options: retrieve the location every 3 seconds
//
var watchID = navigator.geolocation.watchPosition(onSuccess, onError, { frequency: 3000 });

http://docs.phonegap.com/en/1.0.0/phonegap_geoplace_geoplace_geoplace.md.html#geoplace.watchposition

友情链接