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Closed 11 years ago.

我在寻找一些脚本帮助, 使变数的电子邮件输出部分隐藏在 @ like I have email 之前。

[email protected]

我需要在输出中将“随机”的明星放在那里,比如:

ver***@gmail.com
verys*********************@gmail.com
ve*@gmail.com

但不喜欢:

ver***mail.com
verysecre****ail.com

只是随机使用恒星(或静态),

我试过这样

$output = substr_replace($val,  ******** , 2, 7);

美元 = 美元电子邮件 ;

Answer 1

$mail = "[email protected]";

$mailparts = explode("@", $mail);

$output = substr($mailparts[0],0,rand(2,5)) . str_repeat("*",rand(1,16));
$output .= "@" . $mailparts[1];

Answer 2

怎么样的东西,比如:

$asterisks = "";
for($i = 0; $i < strlen(substr($address, 0, strpos($address, "@"))); $i++)
    $asterisks = $asterisks . "*"; //This loop sets the required number of asterisks
$address = str_replace(substr($address, 0, strpos($address, "@") - 1), $asterisks); 
//everything before the  @  is replaced by an asterisk

Answer 3

使用子字符串的阅读方法比较容易:

$emails = array(
     [email protected] ,
     [email protected] ,
     [email protected] ,
);

function obfuscate_email($email) {
    $at_position = strpos($email,  @ );
    $chop = rand(1, $at_position - 1);
    $mask = str_repeat( * , rand(4, 8));

    $partial_address = substr($email, 0, $chop);
    $domain = substr($email, $at_position);
    return $partial_address . $mask . $domain;
}

foreach($emails as $email) {
    var_dump(obfuscate_email($email));
}

// Output:
// string(18) "ver*****@gmail.com"
// string(24) "exam********@example.org"
// string(17) "s****@example.com"

可在上找到一个运行中的示例。

正如你所看到的,我已将代码纳入一个功能,以便更容易使用。该功能将为您提供一个模糊的电子邮件地址,地址如下:

A random chop of the original address (taking into account its length)
A random mask of asterisks

如果是我本人实际执行此函数的话,我会确保我试图混淆的电子邮件地址长度超过3个字符,并适当调整 $chop 长度,以便你能够确定你正在尽可能地隐藏。

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