有可能是蒂瓦尔问题...
I have 2 directories within a Java projects that represent (lets say) model and a view. These 2 directories are mapped in eclipse as two source folders, both on build path.
查看类可以使用模型类,第二个方向(模型使用视图)不允许使用。
以这种方式配置 Eclispe 是否合理?
Example (in IDE, while coding):
I can use aClass from model in view logic (class can be imported and so on).
I cannot use aClass from view in model logic (java error generated by Eclipse).
提前感谢:)
您应该使用默认 Java < a href=" http:// en.wikipedia. org/ wiki/ Java_ package" rel = “ nofollow” > package
为了防止您的模型课程从您的视图包中获取任何东西,您应该确保您在视图包中的所有课程都有 < a href=" http://docs.oracle.com/javase/tuative/java/javaOO/ access control.html" rel=“nofollow” >modacter of protected (或更低)。
为了确保您的观点能够使用您模型包中的类,您应该确保模型包中的所有类(或者至少是您想要访问的类)都有一个modacter of public 。
如果您计划使用 < code> OSGi < /code > 并为查看和模型创建两个不同的工程, 您就可以实现这一点。 如果某个特定项目的类别将 < code> ViewProject 改为 < code > modelProject , 则无法( imported), 除非 ViewProject 在 < code> Menifest. mf 文件中将包含该类的软件包标记为 < em > export 软件包 < / em >, 而模型工程则标记为 < em > import 软件包 。
You can do this by splitting to 2 projects: model and view and add dependency between them. I don t think it is possible within one project in Eclipse. But you can write a simple processor via JSR269 to implement this (check imports).
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