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如何为身份字段创建日期
原标题:How to create a date for identity field

使用 SQL 服务器

我想为身份字段做一个日期栏...

表1 表1 表1

Date_ (Identity Field)

20123
20124
20125
20125
....
....
18901

从表1,最大(日期_)为20125。

所以 20125 应该是当前日期 05/23/2012 mm/dd/yyyyyy

从表1, 我要从最大( date_) 字段到 min( date_) 字段的日期

预期产出预期产出

Date_  Correct Date

20123 05/21/2012 
20124 05/22/2012
20125 05/23/2012
20125 05/23/2012
....  .....
....  .....
18901 02/18/2004   Approximately

如何为此查询

需要 SQL 查询帮助

最佳回答

我无法理解你为什么需要这一点,而18901的值似乎并不正确。我也想了解日期"的意义,http://www.canoe.ca/HockeyRocketRichardGallery/24.html" rel=“nofollow”\\\"code>1957-04-17。

select dateadd(day, Date_,  19570417 )
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