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综合框架声明问题: MySQL
原标题:IF statement issues: MySQL

我有一张表格叫做 contact

我在表格中标有 name 的字段和标有 email 的字段。

在名称字段中,我有一个数值为 Ryan 的行和一个空白的电子邮件字段。

我想运行一个如果有语句的话, 这样它将会在 a href=" "/cdn- cgi/l/email-protect" 类中插入电子邮件 <\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\在\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\

如果它没有发现匹配, 那么我要它插入行 。

至今为止,我尝试过这一点:

 IF name =  Ryan 
 THEN INSERT INTO contact (email) VALUES ( [email protected] ) 
 ELSE
 INSERT INTO contact (name, email) VALUES ( Ryan ,  [email protected] )
 END IF;
最佳回答

解决办法是将问题中的查询纳入存储程序

问题回答

我可能真的错了 但接下来的代码工作不会吗?

UPDATE contact SET email= [email protected]  WHERE name= Ryan ;

如果名称列是主密钥, 您可以使用替换命令

REPLACE INTO contact (name, email) VALUES ( Ryan ,  [email protected] )

在我看来, 您的表格中应该有密钥或独特的字段。 例如, 如果名称是独一无二的字段, 您可以使用类似的东西 。

INSERT INTO contact (name, email) VALUES ( Ryan ,  [email protected] ) ON DUPLICATE KEY UPDATE email = "[email protected]"

你能改变你的餐桌计划吗?





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