Question

如何比较 Groovy 忽略日期的日期? 类似 : < pargen@ MM- yyyyyy_ 1 & gt; MM- yyyy_ 2/ strong >

Answer 1

你可以做到这一点:

int compareIgnoringDays( Date a, Date b ) {
  new Date( a.time ).with { newa ->
    new Date( b.time ).with { newb ->
      newa.set( date:1 )
      newb.set( date:1 )
      newa.compareTo( newb )
    }
  }
}

你可以测试一下:

Date a = Date.parse(  yyyy/MM/dd ,  2012/05/23  )
Date b = Date.parse(  yyyy/MM/dd ,  2012/05/24  )
Date c = Date.parse(  yyyy/MM/dd ,  2012/06/01  )

assert compareIgnoringDays( a, b ) == 0
assert compareIgnoringDays( b, a ) == 0
assert compareIgnoringDays( a, c ) == -1
assert compareIgnoringDays( c, a ) == 1

另一种不同的写法是:

int compareIgnoringDays( Date a, Date b ) {
  [ a, b ].collect { new Date( it.time ) }   // Clone original dates
          .collect { it.set( date:1 ) ; it } // Set clones to 1st of the month
          .with { newa, newb ->
            newa.compareTo( newb )           // Compare them (this gets returned)
          }
}

Answer 2

您可以比较两个这样的日期 :

def myFormat =  MM/dd/yyyy 
if(Date.parse(myFormat,  02/03/2012 ) >= Date.parse(myFormat,  03/02/2012))
{...}

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