能否用空壳脚本回响一下 正在运行的指令?
(没有将 - X 放在牛排中打开调试模式。 这不是调试进程的一部分 )
感谢 谢谢
[编辑:更多细节]
假设我有这样的剧本:
#! /bin/sh
clear
cd ~/home/
我如何将执行的两个命令( cd 和 clear )打印到控制台?
在我版本的 /bin/sh (Debian Almquist Shell, show) 上,除了 -x 之外没有其他方法来得到这种行为。回声命令也是 < code>-x 的 only 效果,所以我认为没有理由不使用它。
echo $0
这将回溯命令行中的第一个单词。 如果您指定一个相对路径, 如“ / bin/ test ”, 它将显示整个路径, 您可能想要 :
echo $(basename $0)
那只会反响"测试" 而不是"/bin/测试"
脚本通常在错误信息中使用0美元,而不是硬编码名称,因为程序可以从符号链接中重新命名或调用。
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