有没有办法缩短下面2号代码的线?
for i = 1:length(dataStructure)
if dataStructure(1,i) == 100000000 || dataStructure(2,i) == 100000000 % this line
dataStructure(:,i) = NaN;
end
end
我本以为以下各点就足够了(但这行不通):
if dataStructure(:,i) == 100000000
换句话说, 我如何检查一个数组的一列中是否存在数字? 这里的问题是, 我无法预测数据结构是否有一行或两行, 因此无法使用嵌套环绕, 因为每次数据结构只有一行就会造成错误 。
if any(dataStructure(:,i) == 100000000)
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