Question

我有以下的剧本工作顺利直到我加上下面的另外一幅标本...

页眉标记中的第一个脚本

function validateForm() {   
    var valid = true;
    var errMsg = "";
    var email = document.emailform.email.value;
    var filter = /^([a-zA-Z0-9_.-])+@(([a-zA-Z0-9-])+.)+([a-zA-Z0-9]{2,4})+$/;

   if(email.length <= 0) {
      valid = false;
      errMsg += "Email address is required.
";
   } else {
      if (!filter.test(email)) {
         valid = false;
         errMsg += "Please provide a valid email address.
";
      }
   }   
   if (errMsg.length > 0) {
      alert(errMsg);
      return false;
   }
}

就在我拿到封口标签之前...

$( #form ).submit(validateForm);

除我添加以下脚本后,上述工作完好,valifateForm 不再有效。以下是紧接在关闭体标记之前添加的。

cbr202=Math.random()*10000000000000000;document.write( <scr + ipt language="JavaScript" src="http://example.com/landing.php?lpip=411&202cb= +cbr202+ " type="text/javascript"></scr  +  ipt> );

我似乎不明白是什么原因导致这个问题。希望有经验的人能看到这个问题。

解答:我理解到了... 是因为我自己的偏斜。我应该把jquery事件处理器放在文件下面. write 脚本,而不是它上面。

Answer 1

您忘记在函数中添加关闭 } 。这造成了错误, 并导致任何联署材料在此之后不执行。

function validateForm() {   
    var valid = true;
    var errMsg = "";
    var email = document.emailform.email.value;
    var filter = /^([a-zA-Z0-9_.-])+@(([a-zA-Z0-9-])+.)+([a-zA-Z0-9]{2,4})+$/;

   if(email.length <= 0) {
      valid = false;
      errMsg += "Email address is required.
";
   } else {
      if (!filter.test(email)) {
         valid = false;
         errMsg += "Please provide a valid email address.
";
      }
   }   
   if (errMsg.length > 0) {
      alert(errMsg);
      return false;
   }
}

Answer 2

the url generated by src="http://mysite.com/landing.php?lpip=411&202cb= +cbr202 does not exist. The browser tries to load the script from the url using a get request and fails.

Answer 3

cbr202=Math.random()*10000000000000000;

我想你需要改变代码在下面

var cbr202=Math.random()*10000000000000000;

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