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Z-顺序曲线中的下一次迭代
原标题:Next iteration in z-order curve
最佳回答

OK 这里 s 这里有“ 平整” 添加算法, < code> < /code > 和 < code> 和 < code> < y < /code > 是输入和输出, 并且假定间断坐标中最低的顺序位是 x (与 < a href=> 中相同) http://en.wikipedia.org/wiki/Z- order_curve" rel= "nofol" > the wikipedia arts

int carry = 1;
do
{
    int newcarry = x & carry;
    x ^= carry;
    carry = newcarry;
    newcarry = (y & carry) << 1;
    y ^= carry;
    carry = newcarry;
} while (carry != 0);

我确实测试过 但只是一点点而已

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