Question

我如何才能使这个 app. locals. user 成为返回值而不是函数? 现在我必须运行 app. locals. user (). name 。

我怎样才能成功运行 app.locals.user.name ?

    app.locals.user = function(){
            if(typeof(req.session.user) !=  undefined ){
                console.log(req.session.user.name.full);
                return req.session.user;
            }else{
                return false;
            }
        };

Answer 1

https:// developmenter.mozilla.org/en/JavaScript/Reference/Global_Objects/Objects/Objects/DefineGetter"rel="不跟随"\\\defineGetter_/a>:

app.locals.__defineGetter__("user", function() {
    if(typeof(req.session.user) !=  undefined ) {
        console.log(req.session.user.name.full);
        return req.session.user;
    } else {
        return false;
    }
});

Edit :_defineGetter_似乎被贬低,

Object.defineProperty(app.locals, "user", { get : function() {
    if(typeof(req.session.user) !=  undefined ) {
        console.log(req.session.user.name.full);
        return req.session.user;
    } else {
        return false;
    }
});

Answer 2

仅 返回任何可变内容;

Javascript 没有键入, 所以您不能真的做任何事情来将此输入函数签名。

function foo() {
    var x = { a : 10, b : 20};
    return x;
}

var y = foo();
debug(y.a);  //prints 10

Answer 3

您可以立即执行该函数,将结果存储为变量:

 app.locals.user = (function(){
            if(typeof(req.session.user) !=  undefined ){
                console.log(req.session.user.name.full);
                return req.session.user;
            }else{
                return false;
            }
        })();

友情链接