我正在尝试获取所有没有属性值的选项值。 所以我想要它获取选项设置, 如
我有 $ (# 高级搜索搜索系统选项: not( [value=“ )) 但我需要的是相反的。 这个: no() 命令的反面是什么?
简单使用常规 CSS 属性选择器 :
$( #advancedSearchWrap option[value=""] );
如果您想要的不是 non , 而是 only 您可以使用 filter () ()
这也有效。
$morphemes.not( [data-width] );
$morphemes.not( :not([data-width]) ); //Double Negative logic, derp derp.
难道它只是减去:不是选择者吗?把它从你的表达式中删除,它应该有效。
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