Bash将箭指向“else”, 用挑衅性的抱怨语气说“语法错误”。
awk {if($3 != 0) a = ($3/$4) print $0, a; else if($3==0) print $0, "-" } file > out
为什么?
您忘记了在区块周围的牙套, 和区块内语句之间的分号 。
awk {if($3 != 0) {a = ($3/$4); print $0, a;} else if($3==0) print $0, "-" } file > out
尝试代码
awk {s=($3==0)?"-":$3/$4; print s}
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