Question

I am sending an xml response from my servlet to my html page. I receive it via the xmlresponse object of the xmlhttprequest object. My xml document contains a xsl:stylesheet as an element I want to extract this element and execute that xslt code in my java script.
Is it possible? This is my xml code :

<samlp:AuthnRequest xmlns:samlp="urn:oasis:names:tc:SAML:2.0:protocol"
Version="2.0" IssueInstant="2012-05-22T13:40:52:390" ProtocolBinding="urn:oasis:na
mes:tc:SAML:2.0:bindings:HTTP-POST" AssertionConsumerServiceURL="localhos
t:8080/consumer.jsp">
<UserID>
   xyz
</UserID>
<testing>
   text
</testing>
<saml:Issuer xmlns:saml="urn:oasis:names:tc:SAML:2.0:assertion">
   http://localhost:8080/saml/SProvider.jsp
</saml:Issuer>
<xslt>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" >
<xsl:output method="text" />
<xsl:template match="/">
UserID : <xsl:copy-of select="//UserID"/>
testing : <xsl:copy-of select="//testing"/>
</xsl:template>
</xsl:stylesheet>
</xslt>
</samlp:AuthnRequest>

Once I get this xml string from the ajax response, I want to convert it into xml, extract the xslt part and execute it and show the output in a text area.
EDIT2
What is wrong with this code :

    var xmlDoc=xmlhttp.responseXML;
     //var xmltext=new XMLSerializer().serializeToString(xmlDoc);
     var xsltProcessor = new XSLTProcessor();
var element=xmlDoc.getElementsByTagNameNS("http://www.w3.org/1999/XSL/Transform","stylesheet");//
 //document.forms[ my ][ signature ].value=xmltext;
var stylesheet=xsltProcessor.importStylesheet(element[0]);
var result=xsltProcessor.transformToDocument(xmlDoc);
 var xmltext1=new XMLSerializer().serializeToString(result);
document.forms[ my ][ signature2 ].value = xmltext1;

The output(xmltext1) for the xslt transformation is -

<transformiix:result xmlns:transformiix="http://www.mozilla.org/TransforMiix">
UserID : 1212

Testing : 1212
</transformiix:result>

但如果您在 xslt 代码中看到, 输出方法设置为“ 文本 ” 。那么为什么 xml 标签包含在输出中?

Answer
This gives the exlpanation for edit2. Thanks for the answers:)

Answer 1

我只能用最新的染色体来测试它:

var getNsResolver = function (element) {
  var ns = {
    samlp:  urn:oasis:names:tc:SAML:2.0:protocol ,
    xsl:  http://www.w3.org/1999/XSL/Transform 
  };

  return function (prefix) {
    return ns[prefix] || null;
  };
};

var handleResponse = function (xhr) {
  var
    doc = xhr.responseXML,
    xsl = doc.evaluate( /samlp:AuthnRequest/xslt/xsl:stylesheet , doc, getNsResolver(doc.documentElement), XPathResult.ANY_TYPE, null).iterateNext(),
    processor = new XSLTProcessor(),
    result;

  processor.importStylesheet(xsl);
  result = processor.transformToFragment(doc, document);

  document.getElementById( foo ).value = result.textContent;
};

window.addEventListener( load , function () {
  var request = new XMLHttpRequest();
  request.addEventListener( load , function (evt) {
    handleResponse(request);
  }, false);

  request.open( GET ,  sample.xml , true); // sample.xml contains the xml from the question
  request.send();
}, false);

Answer 2

这是我从 xmlHttpRequest (在您的情况下, ns=xsl, 未测试) 获得命名空间 xml 时所用的方法 :

var xml=xhr.responseXML;
var elts = (xml.getElementsByTagNameNS)?xml.getElementsByTagNameNS("ns","tag"):xml.getElementsByTagName("ns:tag");

请注意,如果服务器返回完善的 xml, 您只能使用响应XML。否则, 您需要剖析 xhr. refuseText 。

Answer 3

I m using this ATM, works great! Its a parser written on jQuery

http://www.jongma.org/webtools/jquery/xslt/

友情链接