Question

It s difficult to tell what is being asked here. This question is ambiguous, vague, incomplete, overly broad, or rhetorical and cannot be reasonably answered in its current form. For help clarifying this question so that it can be reopened, visit the help center.

Closed 12 years ago.

I can t understand why i get supplied argument is not a valid? My codes belove

db connect.class.php http://ideone.com/AILC9

http://ideone.com/wIbL3" rel="nofollow" >http://ideone.com/wIbL3

http://ideone.com/OQSg9” rel=“no follow”>http://ideone.com/OQSg9

index.php http://ideone.com/Zp6sF

当我运行索引.php,我可以得到这个代码:

<html>

 <head>

  <title>   <br />
<b>Warning</b>:  mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in <b>C:AppServwwwilkclassgetdata.class.php</b> on line <b>21</b><br />
  </title>

  <meta name="description" content="<br />
<b>Warning</b>:  mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in <b>C:AppServwwwilkclassgetdata.class.php</b> on line <b>21</b><br />
" />

  <meta name="keywords" content="<br />
<b>Warning</b>:  mysql_fetch_assoc(): supplied argument is not a valid MySQL result resource in <b>C:AppServwwwilkclassgetdata.class.php</b> on line <b>21</b><br />
" />

 </head>

</html>

Answer 1

您的 Mysql 连接/ 请求失败。在每次拨打信头以显示错误后, < code> echo mysql_ error () 。

同样在您的 sayfa Header () 方法中,最后两行将永远无法执行,因为您有两行返回, 一旦您 return 功能执行结束, 就会有两行返回。

Answer 2

在您的数据库连接类中,您没有检查连接本身是否已经建立。此错误显示没有建立有效的 Mysql 连接, 因此该变量没有附加资源。您可能没有错误, 因此您应该总是退出/ 中止, 如果您的连接 = 无效。请确认您的数据库证书正确。

Answer 3

将函数更改为此

protected function getData()
{
    $result = mysql_query($this->sql, $this->database) or $this->error = mysql_error();
    if($result !== false) die(mysql_error());

    while($rs = mysql_fetch_assoc($result))
    {
        $this->data[] = $rs;
    }
    $dataObject = (object) $this->data;
    return (array) $this->data;
}

它会返回一个错误, 错误会告诉您查询有什么问题

友情链接