我希望第一个项目默认会扩展, 但与jquery有麻烦。 我尝试了几个不同的角度, 却毫无用处。 任何帮助都会非常感激!
The HTML: <a href="javascript:void(0)" id="m1">Get Selected id s</a> The Function: jQuery("#m1").click( function() { var s; s = jQuery("#list4").getGridParam( selarrrow )...
我希望第一个项目默认会扩展, 但与jquery有麻烦。 我尝试了几个不同的角度, 却毫无用处。 任何帮助都会非常感激!
您可以保留第一个项目默认以下行扩展
$( #collapser li:first-child > ul ).show();
它所做的是选择 first li
,然后在 li
和 show
中选择 ul
。
< a href=> "http://api.jquery.com/ first- child-selector/" rel="nofol" > First Child Shoppor
"http://jsfiddle.net/joycse06/trrJp/2/" rel="nofollow" >work Fiddle
如果您的问题只是您想要打开第一个项目, 在您设置了所有菜单时, 您可以做类似的事情 :
$( #menu li: first). sliideToggle ();
();
或者您可以模拟点击 :
$( #menu li: first) 点击 ();
实际代码取决于你的实际执行情况 以及如何打开它 但一般的想法是 触发第一个要打开的元素
The HTML: <a href="javascript:void(0)" id="m1">Get Selected id s</a> The Function: jQuery("#m1").click( function() { var s; s = jQuery("#list4").getGridParam( selarrrow )...
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