Question

我需要帮助设计一个PHP代码实现以下目标:

Access a website (www.example.com)
Download its source code into a string variable
搜索此指定字符串以查找特定内容,例如

基本上我需要搜索 title=\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\



谢谢大家

Answer 1

您可以使用"http://php.net/manual/en/class.domdocument.php" rel=“nofollow”>PHPDOM :

$text = file_get_contents( http://example.com/path/to/file.html );
$doc = new DOMDocument( 1.0 );
$doc->loadHTML($text);
foreach($doc->getElementsByTagName( div ) AS $div) {
    $class = $div->getAttribute( class );
    if(strpos($class,  news ) !== FALSE) {
        if($div->getAttribute( title ) ==  news alert ) {
            echo  title found ;
        }
        else {
            echo  title not found ;
        }
    }
}

http://api.querypath. org/docs/"rel="nofollow"\\\\\ uery path , 试图模仿 jQuery 服务器侧面 :

$text = file_get_contents( http://example.com/path/to/file.html );
if(qp($text)->find( div.news[title="news alert"] )->is( * )) {
    echo( title found );
}
else {
    echo( title found );
}

Answer 2

您可以使用“http://www.php.net/manual/en/class.domxpath.php' rel = “no follow” >DOMXPath 来找到它:

$dcmnt = new DOMDocument(); $dcmnt->loadHTML( $cntnt );
$xpath = new DOMXPath( $dcmnt );
$match = $xpath->query("//div[@title= news alert ]");

echo $match->length ? "Found" : "Not Found" ;

说明:"http://codepad.org/CLDE8XCQ" rel=“no follow'>http://codpad.org/CLDE8XC/a>

Answer 3

这很简单:

$html = file_get_contents( http://site.com/page.html );
if (strpos($html, title="news alert" )!==false)
 echo  title found ;

Answer 4

$page = file_get_contents( http://www.example.com/ );
if(strpos($page, "title="news alert"")!==false){
    echo  title found ;
}

Answer 5

$url =  http://www.example.com/ ;
$page = file_get_contents($url);

if(strpos($page,  title="news alert" ) !==false || strpos($page,  title= news alert  ) !==false)
{
    echo  website with news alert found ;
}
else
{
    echo  website not found ;
}

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