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我如何从一个表格中选择一行, 而该表的值行在另一个表格中不存在?
原标题:How do I select a row from one table where the value row does not exist in another table?
  • 时间:2012-05-24 09:16:42
  •  标签:
  • sql

假设我有两个相同的表格,A和B, 与“x”行相同。

我想选择 A 中的所有元素, 其中 A 中的 x 值不是 B 中 x 值的任何值 。

我该怎么做?

最佳回答

你也可以做这样的事情:

SELECT * FROM TableA
LEFT JOIN TableB on TableA.X = TableB.X
WHERE TableB.X IS NULL

(对于您问题中非常直截了当的例子来说, 一种 NOT EXISTS / < code> NOT IN 的方法可能更可取, 但是, 您真正的查询是否更为复杂, 这是您可能想要考虑的一个选项; 如果您想要从表B中找到匹配位置的 som 信息, 但也想知道在哪里( / em/ sub) < / em/ sub > 。

问题回答

I m having some trouble to understand what you need.
Anyway try this:

SELECT * FROM tableA 
WHERE x not IN (SELECT x FROM tableB)
select *
from TableA
except
select *
from TableB

最快的是左队

SELECT * FROM A LEFT JOIN B ON A.X = B.X WHERE B.X IS NULL

使用它 :

select * from a where x not in (select x from b)




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