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从字符串中删除重复字符, 并使用递归只保留单个事件
原标题:Remove duplicate character from a string and keep only single occurrences using recursion

我尝试从字符串中删除多处字符, 并仅保留一次( 第一次), 使用循环 。 重复可以是连续的, 也可以是任意的 。


e.g. Input:- RAMA, Output:- RAM i.e It removed only second occurrence of char A and printed RAM . I am getting stuck at calling recursive function remove with stack values as it is always being called with same value A . Please review once.


class RecursionRemoveDuplicatesFromString {
    String newStr="";
    String subs = "";
    String remvDupl = "";
    int i = 0;
    int j = 0;
    int count = 0;
    String removeDuplicates(String toSubs){
        //String toSubs = s;
            return toSubs;
        if(i <= toSubs.length()-2){
            subs = toSubs.substring(i,i+1);
            subs = toSubs.substring(i);
            return subs;
        //String subs = i <= toSubs.length()-2 ? toSubs.substring(i,i+1) : return toSubs.substring(i,i+1);
        return newStr;
    void remove(String s, String subs){

            if(j <= s.length()-2){
                remvDupl = s.substring(j,j+1);
                remvDupl = s.substring(j);
                //return remvDupl;
            //String remvDupl = j < s.length()-2 ? s.substring(j,j+1) : "";
                count += 1;
                //newStr += subs;
                    newStr += subs;
        //remove(s, remvDupl);
        count = 0;
    public static void main(String[] args) {
        String s = "RAMA";
        RecursionRemoveDuplicatesFromString remvDupli = new RecursionRemoveDuplicatesFromString();


import java.util.LinkedHashSet;
public class Main {
    public static void main(String[] args) {
        String s = "RAMA";
        LinkedHashSet<String> set = new LinkedHashSet<>();
        char[] c1=s.toCharArray();
        for(int i=0;i< c1.length;i++){
        System.out.println(set); //[R, A, M]

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