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使用迭代器打印每组成员
原标题:Using an iterator to print out every member of a set

我试图用一个代号打印每组的每个成员。 从其他的堆积流答案中可以看出, 我有一个正确的格式。 当我运行这个代码时, 它的输出是正确的, 我的集大小为 3, 但只有一次输出 。 如果我不与 iter 的对齐, 视觉工作室会丢出一个运行时的例外, 说“ 映射/ 设置的代号是不可减损的 。 知道为什么吗?

int main()
{
set<int> myset;
myset.insert(5);
myset.insert(6);
myset.insert(7);
set<int>::iterator iter;
cout<<myset.size()<<endl;
int ii=0;
for(iter=myset.begin(); iter!=myset.end();++iter);{
    //cout<<(*iter)<<endl;
    ii+=1;
    cout<<ii<<endl;
}
return 0;
}
最佳回答

您在此行中有额外的 < code>; :

for(iter=myset.begin(); iter!=myset.end();++iter);{

这意味着循环体实际上是空的, 且以下行只执行一次 。

因此,将该行修改为:

for(iter=myset.begin(); iter!=myset.end();++iter) {
问题回答

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