Question

我试图使用 Go s 反射系统来检索函数的名称,但在按类型调用名称方法时,我得到了空字符串。这是预期的行为吗?

这是我如何解决问题的简单例子:

package main

import "fmt"
import "reflect"

func main() {
    typ := reflect.TypeOf(main)
    name := typ.Name()
    fmt.Println("Name of function" + name)
}

Answer 1

解决办法是使用"http://golang.org/pkg/runtime/#FuncFORPC" rel=“noreferrer” >FuncForPc ,它返回一个 /func 。

此返回 "main. main" :

package main

import "fmt"
import "reflect"
import "runtime"


func main() {
    name := runtime.FuncForPC(reflect.ValueOf(main).Pointer()).Name()
    fmt.Println("Name of function : " + name)
}

如果您想要 "main" , 请标记它。

Answer 2

package main

import "fmt"
import "runtime"

func main() {
    pc, _, _, _ := runtime.Caller(0)
    fmt.Println("Name of function: " + runtime.FuncForPC(pc).Name())
    fmt.Println()

    // or, define a function for it
    fmt.Println("Name of function: " + funcName())
    x()
}

func funcName() string {
    pc, _, _, _ := runtime.Caller(1)
    return runtime.FuncForPC(pc).Name()
}

func x() {
    fmt.Println("Name of function: " + funcName())
    y()
}

func y() {
    fmt.Println("Name of function: " + funcName())
    z()
}
func z() {
    fmt.Println("Name of function: " + funcName())
}

产出:

函数名称: 主. main

函数名称: 主. main
Name of function: main.x
Name of function: main.y
Name of function: main.z

Answer 3

import runtime

func funcName() string {
    pc, _, _, _ := runtime.Caller(1)
    nameFull := runtime.FuncForPC(pc).Name()    // main.foo
    nameEnd := filepath.Ext(nameFull)           // .foo
    name := strings.TrimPrefix(nameEnd, ".")    // foo
    return name
}

Answer 4

这是用于返回函数名称的测试生产即时实用功能。

注1:我们正在处理从FuncFORPC 调出零指针的可能性。

Note 2: optFuncLevel is just a friendly name for stack frame level. This gives us the flexibility of using this within another layer of utility functions. A direct call from say main would just pass 1 (or nothing since default), but if I am calling FunctionName in a log enriching function, say PrettyLog() that is called from regular code, I would call it as FunctionName(2) in the call from PrettyLog, so the function name returned is the name of the caller of PrettyLog, not PrettyLog itself.

// FunctionName returns the function name of the caller
// optFuncLevel passes the function level to go back up.
// The default is 1, referring to the caller of this function
func FunctionName(optFuncLevel ...int) (funcName string) {
    frameLevel := 1 // default to the caller s frame
    if len(optFuncLevel) > 0 {
        frameLevel = optFuncLevel[0]
    }

    if pc, _, _, ok := runtime.Caller(frameLevel); ok {
        fPtr := runtime.FuncForPC(pc)
        if fPtr == nil {
            return
        }
        // Shorten full function name a bit
        farr := strings.SplitN(fPtr.Name(), "/", 2)
        if len(farr) < 2 {
            return
        }
        return farr[1]
    }

    return
}

友情链接