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提交后在下降时显示选中的数值
原标题:Show selected value in dropdown after submit

hi guys i added dropdown field to form however after i submit the form if there is any error dropdown resets itself how can keep to value after validation thanks a lot for your any helps and idea here is my code

<td><select id="country" name="country"  style="width:150px;">
         <option value="-1">Select</option>
     <?php
$query = "SELECT country_id, name FROM countries ";
$result = mysql_query($query);
while($row = mysql_fetch_array($result))
{
  echo "<option value="".$row[ country_id ]."" >".$row[ name ]."</option>
  ";
}
?>
</select></td>
<td><?php echo $form->error("country"); ?></td>
最佳回答

通常您会设置默认选项, 属性为 < code> 选择的 , 与当前选中值绑在一起。 因此, 在此情况下, 选项等于 < code>$_POST[ 国家] 的值 :

while ($row = mysql_fetch_array($result))
{
    if ($row[ country_id ] == $_POST[ country ])
        $selected = "selected="selected"";
    else
        $selected = "";
    echo "<option value="".$row[ country_id ]."" $selected>".$row[ name ]."</option>
 ";
}

其结果是就适当的选择方案提出以下意见:

<option value="123" selected="selected">456</option>
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