我有几个复选框和一个状态框, 告诉您是否至少检查了一个复选框 。
我还有一个“全/无”复选框,该复选框用于切换复选框,但不会触发分配给每个复选框的更改事件,这样如果使用“全/无”复选框,状态就不会更新。
以下是我的执行情况:
function toggleChecked(status) {
$(".chkbx").each( function() {
$(this).prop("checked", status).change(); // you have to trigger the event
});
}
http://jsfidd.net/2ej3W/1/” >DEMO
通过脚本对输入元素的任何修改将不会触发 change 事件 。
您也可以触发 change () ,同时更新以下内容的修改,
$(this).prop("checked", status).change();
<强度 > 完整代码:
function toggleChecked(status) {
$(".chkbx").each( function() {
$(this).prop("checked", status).change();
});
}
还使用 .prop 而不是 .attr
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