我想比较两个混杂点以确定哪些值可以匹配。例如:
hash1 = {
"hash1_key_a" => 1,
"hash1_key_b" => 2
}
hash2 = {
"hash2_key_a" => 1,
"hash2_key_b" => 3,
"hash2_key_c" => 4
}
# The method here should display the matching keys & values,
# and then delete them from their hashes. For example:
puts "#{hash1_key_a};#{hash2_key_a};1" # 1 is representing the referral we should
# put in for the value
谁能指引我走正确的方向?
哈 沙 子 有 不同 的 钥匙 吗? 这样 、 你 可以 做 这样 的 事 :
hash1.merge(hash2).group_by{|k,v| v}.each{ |v,ks|
puts "#{ ks.map(&:first)* ; };#{ v }"
}
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