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原子类型和线索
原标题:Atomic types and threads

这是本专题之后的下一步: < a href="https://stackoverflow.com/ questions/10737625/modification-data- in-threads" > 修改线索中的数据

class Nginx_sender
{
    private:
        std::atomic_int data;
        boost::mutex mMutex;
   void SendMessage(const std::string &msg)
   {
       mMutex.lock();
       data++;
       mMutex.unlock();

       std::cout << "DATA: " << data << std::endl;
   }

   void NewThreadFunction()
   {
      while(true) {
        mMutex.lock();
         std::cout << data;
        mMutex.unlock();

        boost::this_thread::sleep(boost::posix_time::milliseconds(200));
      }
   }
};
int main()
{
   Nginx_sender *NginxSenderHandle;
   boost::thread sender(boost::bind(&Nginx_sender::NewThreadFunction, &NginxSenderHandle));
   // ...
}

NewTreadFunction 中,数据总是 0,在 SendMessage 中,每当我称之为 SendMessage 时,数据就会改变。 因此,什么是正确的方法来使用这个方法?

最佳回答

删除第二个要绑定的参数中的 & amp; 。 您已经对对象有一个指针, 而这就是您可能尝试使用的。 其次, 指针未初始化, 这也可能是您问题的根源 。 注意, 您必须确定对象在线条连接之前仍然有效 。

int main()
{
   Nginx_sender *NginxSenderHandle = new Nginx_sender  ;
   boost::thread sender(boost::bind(&Nginx_sender::NewThreadFunction, NginxSenderHandle));
   // ...
}
问题回答

为什么你要通过一个 Nginx_sender /code> (双指点) 到 boost::: bind ? 这似乎是错误的, 并解释为什么您的线条似乎在对象的第二个副本而不是主线上操作 。





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