我一分一秒的正反就是这个样子
/[a-z0-9]{40}/i
它将匹配任何字符串中没有任何含有字母和/或数字的空格。
我怎样才能更改它, 这样它至少必须包含至少一个数字和至少一个字母字符, 这样如果字符串是全部数字或所有字母, 那么它就不会匹配?
谢谢 谢谢
/([:alpha:].*[:digit:]|[:digit:].*[:alpha:])/
这就要求一个号码随信或一个号码后的信后。
从您原来的正则, 您似乎想要执行40个字符的总共要求。 为此, 请尝试 :
/^(.*[:alpha:].*[:digit:].*|.*[:digit:].*[:alpha:].*){40}$/
注意 额外的 < code>. {{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{{>>>> s。只要有1个阿尔法和1个位数,其他字符可以是任何东西。只要有40个。}}只要有40个。
如果您想要避免匹配白色空间, 请将每个 < code>.\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\可以\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\
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