如果该函数是:
void foo(struct* bar)
{
}
还有
struct foobar;
只是一个小插曲的事例,那叫唤会响起吗?
foo(foobar);
被当做是一个成员阵列的指针吗?该呼叫是合法还是需要超载?
Is a single instance of struct, will the call foo(foobar); Be treated as if it were a pointer to a one member array? Will the call be legal or does it require an overload?
不 不会的 电话不合法 超载可以让电话起作用
如果函数需要一个指针到 struct ,那么您必须给它一个指针到 struct 。 矩阵是特殊的, 因为它们 decay 到第一个元素的指针。
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