我在想这个代码片段是否真的会存储一个指向由地图管理的物体的指针:
std::map<std::string,MapType> map;
MapType* typePointer;
typePointer = map[someKey];
我在想这个代码片段是否真的会存储一个指向由地图管理的物体的指针:
std::map<std::string,MapType> map;
MapType* typePointer;
typePointer = map[someKey];
typePointer = &map[someKey];
不,
您正在存储 MapType
, 而不是 MapType/code> 在地图中。 因此, 最后一行是一个类型错配, 不会编译 。
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