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在未管理函数中管理类参数吗?
原标题:Managed class parameter in unmanaged function?
  • 时间:2012-05-24 19:59:01
  •  标签:
  • c++
  • c++-cli

我试图重写我的 C# 库, 有点与我的 C++ 执行合并, 在管理的 C++ 中。

我有一个有管理的基级,我也需要在无管理的班级里使用。

我有一个未管理的类(在 #pragma 中未加处理), 该类的函数以我的基类为参数, 然后添加到稍后要引用的矢量中 。

出于某种原因,它不承认gcroot 为关键词。 我猜是因为#pragma中的代码没有管理。

我怎么能做到这一点?

谢谢

亚历克斯

最佳回答

您是对的。 # pragma 中任何未管理的代码都必须是“ 常规” C+++ (它不能包括 C++/ clar 代码 ) 。 如果您想要本地类使用 gcroot, 请不要将代码放在 # pragma 未管理的 # pragma (因为它 does 包含管理代码 ) 。

为何你需要它出现在#Pragma不受管理的地方?

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