我有一些东西可以返回元素清单,但有时元素清单也是元素清单。
这方面的例子如下:
(1 2 3 (4 5) (6 7 (8)))
我似乎无法写一个函数, 将它转换成仅包含元素的列表 。
(1 2 3 4 5 6 7 8)
这里的答案是最初的海报是用来帮助 任何在这个问题上发生的人:
(define (test expresssion)
(cond ((empty? expresssion) null)
((not (list? expresssion)) (list expresssion))
(else (append (test (first expresssion))
(test (rest expresssion))))))
(test (A (B (C) D) A)) ; => (A B C D A)
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