我有两张桌子的轮班和轮班会议。两者之间的关系就像轮班有许多轮班,而轮班属于轮班。
我这样定义轮班模式上的关系
var $name = ShiftSession ;
var $belongsTo = array(
Shift => array(
className => Shift ,
foreignKey => ShiftID
)
);
问题是,我想显示从轮班表变换的变换名称,而不是在轮班表变换ID。
你必须尝试:
$this->ShiftSession->find( all );
这将返回您在 Shift 表格中的相应数据 。
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