Question

我有一个输出是格式化的输出

weight:121p height:6f money:5 update:8 read:62b query:132 etc

我希望输出没有这样的单位

weight:121 height:6 money:5 update:8 read:62 query:132 etc

我尝试了 etcs," 但它排除了输出中字母 p 的每一次发生。



我只想在结肠后移除单位。什么是解决问题的最佳办法?

Answer 1

如果您更喜欢perl:

echo "weight:121p height:6f money:5 update:8 read:62b query:132" 
| perl -pe  s/(w+:d+)w* /$1 /g

Answer 2

sed  s/(:[0-9][0-9]*)[a-z]/1/g

或如果单位的长度可能大于一个字母

sed  s/(:[0-9][0-9]*)[a-z][a-z]*/1/g

Answer 3

echo "weight:121p height:6f money:5 update:8 read:62b query:132 etc"|awk  {$1=substr($1,0,length($1)-1);$2=substr($2,0,length($2)-1);$5=substr($5,0,length($5)-1);print} 

        weight:121 height:6 money:5 update:8 read:62 query:132 etc

Answer 4

这迫使数字以小数的非数字/非点数为数字。

awk  {for (i = 1; i <= NF; i++) {split($i, a, /:/); if (a[2] ~ /^[[:digit:]]/) {$i = a[1] ":" a[2] + 0}}; print}  inputfile

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