Question

表格中的数据如下:

SessionID
S1
S2
S3

i 在另一表2中有以下数据:

EmployeeID | Session
1          | NULL
2          | NULL
3          | NULL

What i would like to do is update/Insert each row example

UPDATE table2 SET Session= (SELECT SessionID FROM TABLE1)
INSERT INTO( COPY each row and insert 2nd row session id from table1)

The Expected Result: TABLE2

EmployeeID | Session
1          | S1
2          | S1
3          | S1
1          | S2
2          | S2
3          | S2
1          | S3
2          | S3
3          | S3

任何洞察都会有所帮助

谢谢

Answer 1

听上去你想在表2中划一行,目前表2中的每一行和表1中每一行的组合,如果是的话。。。。。

BEGIN TRAN

SELECT * INTO #temp FROM TABLE2

DELETE TABLE2

INSERT TABLE2
(
    EmployeeID,
    Session
)
SELECT
    temp.EmployeeID,
    TABLE1.SessionID
FROM TABLE1 CROSS JOIN #temp temp

DROP #TEMP

COMMIT TRAN

Answer 2

将数据插入你的雇员会议(表2):

INSERT INTO EmployeeSession ( EmployeeID, SessionID )
    SELECT Employee.ID, [Session].ID
    FROM Employee, [Session]

Answer 3

我认为MERGE 声明有助于:

MERGE INTO TABLE2 t2
    USING (SELECT t2.EmployeeID, t1.SessionID
FROM TABLE2 t2
CROSS JOIN TABLE1 t1) t
        ON t2.EmployeeID = t.EmployeeID AND t2.Session = t.SessionID
    WHEN NOT MATCHED BY TARGET THEN
        INSERT (EmployeeID, Session) VALUES(t.EmployeeID, t.SessionID)
    WHEN NOT MATCHED BY SOURCE THEN
        DELETE
;

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