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Closed 11 years ago.

http://jsbin.com/uxepap/17/edit

我如何用一个 < code@ lt; span 类= " wrap " & gt; & lt;/ span> 将 < / strong > 从第三个链接连接到最后一个 / strong 链接到最后一个 < strong >?

尝试做出修正, 如果它有效, 链接将会在红色背景上加上折叠。

< parger > 注: 它应该在 a_items var 内包装,然后由 .html (); 显示

<% 1\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\

Answer 1

$( a:gt(2) ).wrap( <span/> );

DEMO 1

或

var links = $( a );
var last = links.filter( :gt(2) );
last.wrap( <span/> );

"http://jsfiddle.net/thecodeparadox/tkpQ6/2/" rel="nofollow"\\\ strong > DEMO 2

Acc或ding to edit

$( div a ).map(function(index, item) {
    if(index > 2) {
        return $(item).wrap( <span class="wrap"/> ).get(0)
    } else return $(item);
});

http://jsfiddle.net/thecodeparadox/tkpQ6/7, rel=“nofollow”>DEMO 3

Answer 2

. wrap 覆盖每个元素。使用 < a href=" http:// api.jquery.com/ wrapAll/" rel="nofollow"\\code > wrapAll 覆盖一组元素 :

last.wrapAll( <span></span> );

Answer 3

var links = $( a ).slice(2, $( a ).length);
    links.wrap( <span/> );

Answer 4

jQuery 拥有 < a href=> http://api.jquery.com/slice/" rel=" no follow"\\\\ code>selice () 将您选中的选择从选中的起始索引过滤到选中的可选终点索引。

这里有一个样本。

var last = $( a )       //store them in last
    .slice(2)           //get third to last
    .remove()           //remove them from the DOM
    .wrap( <span> );    //wrap them in span

友情链接