Question

在我的申请中,我需要用卡布查来验证。我正使用这个链接 : < a href="http://vocublablablaair.nl/webservices/send.php" rel="nofollow" >http://vocublablablaair.nl/webservices/send.php

它返回类似此的字符串 : /webservices/ symp-php- captcha.php?_CAPTCHA&t= 0. 59145200+1338304461

然后,该链接应该称为:http://vocublablablair.nl/webservices/sproy-php-captcha.php?_CAPTCHA&t=0.59145200+1338304461

当我用同样的 HttpClient 调用这个时( 正确的会话曲奇), 它会给出以下错误 :

java.lang.IllegalArgumentException: Illegal character in query at index 94: http://vocublablair.nl/webservices/simple-php-captcha.php?_CAPTCHA&t=0.59145200+1338304461

Answer 1

我解决了问题,做了以下工作:

首先,我得到的所有链接必须是HTML编码使用:

Html.fromHtml(String)

调用正确的 URL :

content = sb.toString(); //the fetched link
String myCookie = "";
//get session cookie from other call.

List<Cookie> cookies = ((DefaultHttpClient)httpClient).getCookieStore().getCookies();
for(Cookie c : cookies){
if(c.getName().equals("PHPSESSID")){
    myCookie = c.getName() + "=" + c.getValue();
    break;
   }
   }

URL url = new URL(Html.fromHtml("http://vocublablair.nl" + content).toString());
URLConnection connection = url.openConnection();
connection.setDoInput(true);
connection.setRequestProperty("Cookie", myCookie);
connection.connect();
Bitmap bit = BitmapFactory.decodeStream(new FlushedInputStream((InputStream) connection.getContent()));

我使用一个粗略的输入量Stream。这里读到 : < a href=" http://twigstechtips.blogspot.com/2011/10/android-load-loading- jpgpng-images- from- url.html" rel=“ nofollow” >http://twigstechtips.blogspot.com/2011/10/android-loading-jpgpng-images- from-url.html

Answer 2

best way is to generate your own captcha image because using third party resources may cause inconvenient for your customers. for generating capthcha in android you could use this simple library : http://simplecaptcha.sourceforge.net/

友情链接