我的c++代码中有：
typedef vector<int> cards;
typedef vector<cards> rows;
typedef vector<rows> matriz;
在我的int main（）中，我尝试用这行初始化一个名为“cartas”的matriz；
63 cin>>n>>m;
66 cartas(n,rows(m, cards(0)));
但是，对于g++，请删除以下错误：
flip.cpp: In function ‘int main()’:
flip.cpp:66: error: no match for call to ‘(matriz) (int&, rows)’
我想取一个n*m矩阵，其中每个位置都有整数向量。
谢谢，现在，我不明白怎么回事。
你的代码是否与以下代码相似：
int n, m;
matriz cartas;
cin>>n>>m;
cartas(n,rows(m, cards(0)));
?
这行不通， 最优的 可供替代的马莉兹·卡塔斯已经是一个初始化。要么在cin语句后定义cartaz
int n, m;
cin>>n>>m;
matriz cartas(n,rows(m, cards(0)));
int n, m;
matriz cartas;
cin>>n>>m;
cartas = matriz(n,rows(m, cards(0)));
Why not just set an array of size n*m vector[]. you can get each row as index % n and column as index % m. Much simpler and cleaner.
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