我有一个字符串 看起来像一个列表,让我们说:
fruits = "[ apple , orange , banana ]"
将它转换为列表对象的方法是什么?
>>> fruits = "[ apple , orange , banana ]"
>>> import ast
>>> fruits = ast.literal_eval(fruits)
>>> fruits
[ apple , orange , banana ]
>>> fruits[1]
orange
正如在评论中所指出的,“http://docs.python.org/library/ast.html'>ast.literal_eval 是`强势的'安全 强势的>。
Safely evaluate an expression node or a string containing a Python expression. The string or node provided may only consist of the following Python literal structures: strings, numbers, tuples, lists, dicts, booleans, and None.
This can be used for safely evaluating strings containing Python expressions from untrusted sources without the need to parse the values oneself.
致"的简单电话 http://docs.python.org/library/forms.html#eval" rel="noreferr"\\ code>eval () 将做:
fruits = eval("[ apple , orange , banana ]")
fruits
> [ apple , orange , banana ]
或如此 < a href="" http://lybniz2.sourceforge.net/safeeval.html" rel="noreferrer" > article 所解释的,
fruits = eval("[ apple , orange , banana ]", { __builtins__ :None}, {})
这一解决方案的优点在于不取决于其他模块。
我认为这是星体 立体电子学的用途
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