这是我要在我的 SQLite3 DB 上运行的 SQL 代码 :
INSTERT 进入 tbl_ type valluess (?,????????????????)
但无论我玩多少 ?
? 我都会得到相同的 “SQL逻辑错误或缺少数据库”
错误,而只是用自定义任意值取代 ?
? 错误,在我的表格中运行并获得记录,因此我推断出我的语法有问题。
解药是什么?
这是我要在我的 SQLite3 DB 上运行的 SQL 代码 :
INSTERT 进入 tbl_ type valluess (?,????????????????)
但无论我玩多少 ?
? 我都会得到相同的 “SQL逻辑错误或缺少数据库”
错误,而只是用自定义任意值取代 ?
? 错误,在我的表格中运行并获得记录,因此我推断出我的语法有问题。
解药是什么?
我不得不道歉,因为我发现问题 部分由Googling 和部分野蛮的武力:
The leftmost SQL parameter has an index of 1
and I was confusing it with the similar clause I read at column
page.感谢您花时间反正;-)
我也有同样的错误,但后来我注意到我拼错了一个参数名称。
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