我有以下不符合预期的前提:
isHistoric == 0 AND (NOT ANY singleToMany.name ==[cd] "searchword")
我期待任何物体在他们单一的ToMany关系中 都有. 字的搜索名... 将不会出现在结果中...
如果我把这个翻到它头上,拿掉它——我只返回一个我不想使用它的结果![如果这有道理]意思是:
isHistoric == 0 AND (ANY singleToMany.name ==[cd] "searchword")
返回第一个前提示例中不想出现的一个结果。
有什么建议吗?
尝试 :
isHistoric == 0 AND (NONE singleToMany.name ==[cd] "searchword")
DOCS 表示 < code> noone 相当于 NOT (ANY...) 。 注意括号的位置 。 因此, 以上应等于 :
isHistoric == 0 AND NOT (ANY singleToMany.name ==[cd] "searchword")
isHistoric == 0 AND singleToMany.name NOT LIKE [cd] "searchword"
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