Question

我想知道如何将 http 响应从服务器转换为可解的 JSON 阵列

        try {
            HttpClient httpClient = new DefaultHttpClient();
            HttpPost postRequest = new HttpPost(
                    "http://riffre.com/chatapp/search.php?format=json");
            postRequest.setEntity(new UrlEncodedFormEntity(nameValuePair));
            ResponseHandler<String> responseHandler = new BasicResponseHandler();
            responsesrch = httpClient.execute(postRequest, responseHandler);

            Log.v("search response", responsesrch);

this is my code where I post a few parameters in form of name value pairs to the server and the value of responseserch that I get is

{"users":[{"user":{"city":"gurgaon","username":"zxc","userid":"6","gender":"Male","images":"0"}},{"user":{"city":"gurgaon","username":"tarun","userid":"5","gender":"Male","images":"0"}},{"user":{"city":"gurgaon","username":"vips","userid":"4","gender":"Male","images":"0"}},{"user":{"city":"gurgaon","username":"rah","userid":"3","gender":"Male","images":"0"}},{"user":{"city":"gurgaon","username":"aak","userid":"2","gender":"Male","images":"0"}}]}

这是用字符串格式, 所以我想知道我怎样才能把这个字符串转换成json阵列, 我不知道我必须如何使用输入流和所有这些实体, 任何帮助都会非常感激。

Answer 1

请看这个,很简单

http://www.androidhive.info/2012/01/andandroid-json-parsing-tutorive/

将 ISIS 转换为字符串

 try {
            BufferedReader reader = new BufferedReader(new InputStreamReader(
                    is, "iso-8859-1"), 8);
            StringBuilder sb = new StringBuilder();
            String line = null;
            while ((line = reader.readLine()) != null) {
                sb.append(line + "n");
            }
            is.close();
            json = sb.toString();
        } catch (Exception e) {
            Log.e("Buffer Error", "Error converting result " + e.toString());
        }

将字符串转换为 Json 对象

try {
            jObj = new JSONObject(json);
        } catch (JSONException e) {
            Log.e("JSON Parser", "Error parsing data " + e.toString());
        }

从对象获取矩阵

 // Getting Array of Contacts
    JSONArray  contacts = json.getJSONArray("users");

Answer 2

您可以使用

GSON
JackSon

如果您想要使用json.org 的默认 Json, 那么请导入 org.json. Json. JsonArray; , 您可以做到 :

JSONArray jsonArray = new JSONArray(yourJsonString);

见:http://www.vogella.com/articles/AndroidJson/article.html 。

Answer 3

这是我工作守则的样本

   jArray = new JSONArray(result);
   JSONObject json_data = null;
   double[] tempLong = null;
   double[] tempLat = null;
   for (int i = 0; i < jArray.length(); i++) {
       json_data = jArray.getJSONObject(i);
       tempLong = new double[jArray.length()];
       tempLat = new double[jArray.length()];
       tempLong[i] = json_data.getDouble("longtitude");
       tempLat[i] = json_data.getDouble("latitude");
   }

我敢肯定,你可以调整它适合你的需要

Answer 4

如果您想要将 Java 对象从/ 转换为 JSON, 您可以查看 : < a href="http://code.google.com/ p/google- gson/" rel=“ nofollow” >google- gson Java 库

Answer 5

有两条代码线

JSONObject jObj = new JSONObject(responsesrch.toString());
JSONArray jArr=jObj.getJSONArray("users");

友情链接