Question

@Override
public View getView(int position, View convertView, ViewGroup parent) {
    ViewTag viewTag;
    if(convertView == null) {
        convertView = myInflater.inflate(R.layout.row_item, null);
        viewTag = new ViewTag((LinearLayout)convertView.findViewById(R.id.row), (TextView)convertView.findViewById(R.id.tv));
        convertView.setTag(viewTag);
    }
    else {
        viewTag = (ViewTag) convertView.getTag();
    }

    viewTag.tv.setText(lvt.getTextAt(position));
    viewTag.tv.setVisibility(View.VISIBLE);

    boolean show = lvt.getShowAt(position);
    if(show) {
        viewTag.tv.setVisibility(View.GONE);
        viewTag.ll.setVisibility(View.GONE);
    }
    else {
        viewTag.ll.setVisibility(View.VISIBLE);
    }

    return convertView;
}

I use above code in BaseAdapter to show list view.
lvt is an application global data.
If show is true, I want to disappear the cell.
But not delete the data.
But my method will not show data, but show the divider line.
How can I do it?

Answer 1

我更改了以下数值 :

@Override
public int getCount() {
    int count = 0;
    int i;
    for(i = 0; i < lvt.sizeTestArray(); i++) {
        if(!lvt.getfiv1At(i)) {
            count++;
        }
    }
    return count;
}

并改变 GEView 的位置如下:

    int i;
    int count = 0;
    for(i = 0; i < lvt.sizeTestArray(); i++) {
        if(!lvt.getfiv1At(i)) {
            if(count == position) {
                position = i;
                break;
            }
            count++;
        }
    }

It seems do well now.
But I am not sure any bug exist now.

Answer 2

如果您想要从 ListView 中 < em> 隐藏 < / em > 项目, 我更希望您使用 seperate < code> lvt (只显示真实), 而不是试图操纵视图。

Answer 3

you can t do what you are asking for.
if BaseAdater.count() return the count of all the itmes(even the ones you don t want to show), than you can t tell the getView() method to "ignore" some of the logic items.

我建议你做的是过滤您的数据列表( 创建一个新的 lvt), 以便只对您想要列表View 显示的项目进行过滤, 并且只有到那时, 适配器才能使用这个新的逻辑数据。

在您的情况中,正如您所怀疑的那样,“lvt.get SshowAt( 位置) =假”应该是您的过滤指示器

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