我知道这听起来很简单 但我没有把两个字符串合并成一个新的字符串
Gtk 条目的 IO 字符串“a” 由
a <- (entryGetText text_field)
目标是将它合并为:
新字符串 = “ 文本 :” +a
Any ideas to accomplish that? Thanks!
使用字符串共解( N) :
do a <- entryGetText text_field
let b = "Text:" ++ a
return b
更简单的是:
do a <- entryGetText text_field
return $ "Text:" ++ a
您也可以玩游戏:
("Text:" ++) <$> (entryGetText text_field)
我相信在哈斯凯尔,弦接弦操作员是。
您使用指派运算符x & lt;- expr / code> 的那一刻, 指定运算符有 exdr * m a/ code > 和 m is some monad, x < /code > 不是一个 m a/code >, 而是一个 a/code > 。 您的情况是, 变量 < code> a/ code > 有类型 string , 而不是 IO String , 所以您可以在纯代码( 如 " hello world " ) 中将其组合成, 例如, ++ a/code > 。
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