Question

当读行! = null 时, 我想在线索中以 SetText () 方法在线索中发布一些消息, 但我发现错误。我无法显示敬礼并使用 setText () 方法。

public void run(){

    Looper.myLooper();
    Looper.prepare();

    try {           
        while(!((line = in.readLine()).equalsIgnoreCase("quit"))){              
            if(line.isEmpty()){
                System.out.println("there is no message");
            }else{                      

     Toast.makeText(this, "Message= " + line , Toast.LENGTH_SHORT).show();
                msgbox.setText(line);
            }               
        }           
    } catch (IOException e) {
        e.printStackTrace();
        System.out.println("Gagal mengirim ACK ke server");
    }

}

Answer 1

你犯了什么错?

这个密码能解决吗?

    try {       

            final StringBuffer strMessage = new StringBuffer();

        while(!((line = in.readLine()).equalsIgnoreCase("quit"))){              
            if(line.isEmpty()){
                System.out.println("there is no message");
            }else{                      

            strMessage.append(line)

            this.runOnUiThread(new Runnable() {
        public void run() {
            Toast.makeText(YourActivity.this, "Message= " + line , Toast.LENGTH_SHORT).show();
             msgbox.setText(strMessage.toString());
            //...
                    }
                });

            }               
        }           
    } catch (IOException e) {
        e.printStackTrace();
        System.out.println("Gagal mengirim ACK ke server");
    }

runOnUitread (...) 运行 UI 线索上的指定动作。如果当前线索是 UI 线索, 则立即执行操作。如果当前线索不是 UI 线索, 则该动作被张贴到 UI 线索的事件队列中。

Answer 2

您无法在 UI 线索以外的任何线索中显示土司。您可以为此使用一个处理器, 或者为此运行 OnUitread 。

 activity.runOnUiThread(new Runnable() {
public void run() {
    Toast.makeText(youractivity.this, "Message= " + line , Toast.LENGTH_SHORT).show();
            msgbox.setText(line);
}
});

Answer 3

您无法用非主线更新您的 UI 。您要么使用 < a href=" http://www.vogella. com/ articles/ AndroidPerformatance/article. html" rel = “ nofollow” > handlers and Threads 。

或者只是尝试一下,为这种活动创建一个折叠式的活动,

activity activityobj= 您的活动; 并在运行中使用 (),

public void run(){

Looper.myLooper();
Looper.prepare();

try {           
    while(!((line = in.readLine()).equalsIgnoreCase("quit"))){              
        if(line.isEmpty()){
            System.out.println("there is no message");
        }else{                      
     activityObj.runOnUiThread(new Runnable() {

        @Override
        public void run() {
Toast.makeText(this, "Message= " + line ,Toast.LENGTH_SHORT).show();
            msgbox.setText(line);

        }
    });


        }               
    }           
} catch (IOException e) {
    e.printStackTrace();
    System.out.println("Gagal mengirim ACK ke server");
}

}

Answer 4

试试这个

1) 在班级内创建一个处理器 :

private Handler mHandler = new Handler() {

    public void handleMessage(android.os.Message msg) {

        Toast.makeText(this, "Message= " + line ,Toast.LENGTH_SHORT).show();
        msgbox.setText(line);
    时 时
时 时;

2) 修改你的代码如下:

public void run(){

Looper.myLooper();
Looper.prepare();

try {           
    while(!((line = in.readLine()).equalsIgnoreCase("quit"))){              
        if(line.isEmpty()){
            System.out.println("there is no message");
        时 时else{                      
           mHandler.sendEmptyMessage(0);
        时 时               
    时 时           
时 时 catch (IOException e) {
    e.printStackTrace();
    System.out.println("Gagal mengirim ACK ke server");
时 时

时时

Answer 5

就是这里了

Handler handler = new Handler();    
public void run(){
Looper.myLooper();
Looper.prepare();
try {           
    while(!((line = in.readLine()).equalsIgnoreCase("quit"))){              
        if(line.isEmpty()){
            System.out.println("there is no message");
        }else{                      
  handler.post(new Runnable() {

                    @Override
                    public void run() {
                         Toast.makeText(this, "Message= " + line , Toast.LENGTH_SHORT).show();
            msgbox.setText(line);
                    }
                });


        }               
    }           
} catch (IOException e) {
    e.printStackTrace();
    System.out.println("Gagal mengirim ACK ke server");
}

}

友情链接