我正在撰写一个 shash 脚本, 该脚本将执行命令, 并将值存储在字符串变量中, 现在我需要将字符串分割为某些字符。 有办法吗? 我无法使用分隔符, 格式也像这样
PV Name /dev/sda2
PV Size 10.39 GB
这里我需要获得 /dev/sda2 和 10.39 GB( 如果可能的话, 仅10.39 个) 和 10.39 GB( 仅10.39 个), 并将其写入新文件。 我不能使用分隔符, 因为空间刚开始。 我还没有做多少粉碎脚本。 有没有办法做到这一点?
echo "${var:8}"
从字符8(零基)开始,将回传 $var 的内容。
脱下从第一个空间开始的任何东西:
data=${var:8}
echo "${data%% *}"
只为获取某些字符, 请使用 < code> cut :
$ echo 1234567 | cut -c2-5
2345
然而,对于您来说, awk 似乎是更好的选择:
$ echo PV Size 10.39 GB | awk { print $3 }
10.39
原文为空间/塔布分隔栏/塔布分隔栏,因此应完全正常工作
http://en.wikipedia. org/wiki/Cut28Unix% 29" rel="nofollow"\\code>cute :
$ echo "PV Name /dev/sda2" |cut -d " " -f 3
/dev/sda2
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