Question

当我运行以下操作时,我得到的有 < code> B.C. ,但我正在尝试获得 < code> BC BC 。

我设置了 arary_search 来进行严格的比较, 为什么它不返回 "BC" ?

如果我通过“Alberta”,我就会得到“AB”,这是正确的。

<?
function cleanProvince($province)
{
    $values = array(
         AB  =>  Alberta ,
         BC  =>  B.C. ,
         BC  =>  British Columbia ,
         ON  =>  Ontario ,
         ON  =>  Onatrio ,
         ON  =>  Ont ,
         NS  =>  Nova Scotia ,
         QC  =>  Quebec 
    );
    if ($key = array_search(@$province, $values, true)) {
        return $key;
    } else {
        return $province;
    }
}
echo (cleanProvince("B.C."));
?>

Answer 1

您无法在一个数组中拥有多个密钥。当您这样做时, 第二个密钥将超越第一个密钥。

$values = array(
     AB => Alberta ,
     BC => B.C. ,
     BC => British Columbia , # Overrides  B.C. 
     ON => Ontario ,
     ON => Onatrio , # Overrides  Ontario 
     ON => Ont , # Overrides  Onatrio 
     NS => Nova Scotia ,
     QC => Quebec ,
);

您再次通过 "B.C." 。 到 cleanProvince 。这不是在 $values , 所以 alaray_search 返回 false , 因此 cleanProvince 返回 \\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\\

Answer 2

如所建议,交换您的键和值将产生预期的结果,并避免拨打 arary_search () ,我只能假定这个电话的间接费用要高得多(在大多数情况下,moot点,但如果迭代调用... )。

function getProvince($name){
    $values = array(
         Onatrio  =>  ON ,
         Ontaroi  =>  ON ,
         O.N.  =>  ON ,
        // ...
    );
    return isset($values[$name]) 
        ? $values[$name] 
        : $name; // or null I suppose
}

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