我有两张桌子 疾病和医生 病致1号医生和许多关系
我使用一个关键字搜索时, 关键字将匹配所有疾病和医生的名字, 并显示结果数据 。 假设我写了“ Karim ” 。 这将从疾病表格中得出疾病名称, 从医生表格中得出医生的名字 。 如果找到正确的匹配点, 它将会选择行 。
我不是在暗中描述如何写出这个查询。 我可以只写一个表格。 这是我的代码:
$query = "select * from disease where diseasename = ".$txtSearch." ";
$query = "select * from doctor where doctorname = ".$txtSearch." ";
但谁能告诉我 如何加入这两个问题?
What you are looking for is the OR keyword.
Try :
$query = "select * from disease dis inner join doctor doc on dis.doctor_id = doc.id where (dis.diseasename = ".$txtSearch." or doc.doctorname = ".$txtSearch." )";
自从你没有在问题中贴上专栏名称以来,我已对这些名称作了一些假设。你必须用数据库中的适当名称取而代之。
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