∗ UNEP/POPS/POPRC.2/1。 iii
C# list file in Director- issue
原标题:C# list file in directory issue
最佳回答
类似于
System.IO.FileInfo[] array = new System.IO.DirectoryInfo("directory_path").GetFiles();
Array.Sort(array, delegate(System.IO.FileInfo f1, System.IO.FileInfo f2)
{
return f2.CreationTimeUtc.CompareTo(f1.CreationTimeUtc);
});
问题回答
我也许会使用准则和清单......这样做的工作:
DirectoryInfo di = new DirectoryInfo("YourPath");
List<FileInfo> files = di.GetFiles().OrderBy(f => f.CreationTime).ToList();
foreach (FileInfo file in files)
{
//do something
}
like:
DirectoryInfo di = new DirectoryInfo("path to folder");
FileInfo[] files = di.GetFiles();
IOrderedEnumerable<FileInfo> enumerable = files.OrderBy(f => f.CreationTime);
foreach (FileInfo info in enumerable)
{
// do stuff...
}
<>strong>EDIT: Update, here s a non-LINQ Solutions
FileInfo[] files = new DirectoryInfo("directory").GetFiles();
Array.Sort(files, delegate(FileInfo f1, FileInfo f2) {
return f2.CreationTime.CompareTo(f1.CreationTime);
});
以上将至少老化。 代表:<代码>return f1.Creationtime.CompareTo(f2.Creationtime);
LINQ solution:
FileInfo[] files = new DirectoryInfo("directory").GetFiles();
var results = files.OrderByDescending(file => file.CreationTime);
1. 使用令 通过按最近创建时间进行分类,否则会利用By教令从最老的到最新的创建时间。
DirectoryInfo baseFolder=new DirectoryInfo("folderName");
FileInfo[] files=baseFolder.GetFiles("");
for(int i=1; i<=files.Length;i++)
for(int j=1; j<files.Length;j++)
{
if(files[j].CreationTime > files[j+1].CreationTime)
{
FileInfo f = files[j];
files[j] = files[j+1];
files[j+1] = f;
}
}
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