我有很长的路要走,有许多国名。 因此,阵列看着这样的情况:
array( Afghanistan , Bulgaria , United States , Bulgaria , ...)
I need to count the number of times each country appears in the string. Is there a quick and nifty way of doing this, i.e., some kind of magical preg_match_all which receives an array of patterns, or must I iterate through all countries?
你们可以使用这样的东西:
$country_names = array( Afghanistan , Bulgaria , United States , ...);
$country_names_preg = "/(" . implode("|", $country_names) . ")/";
preg_match_all($country_names_preg, $long_string, $matches);
//$matches will contain all of the country matches.
$echo "found: " . implode(", ", $matches);
// There would ideally be a check to make sure that $matches had something in it!
我只是通过贵国使用一个h(联系阵列)和 lo:
// Count:
$country_names = array( Afghanistan , Bulgaria , United States , ...);
$country_count = array();
foreach ($country_names as $name) {
$country_count[$name]++;
}
// Then display:
foreach ($country_names as $name) {
echo "Found " . $country_count[$name] . " occurrences of $name.
";
}
如果您希望得到一些空白(但并不迅速执行),则考虑Aho Corasicks s. Here s implementation in PHP。
$yourtmplongstring = strtolower($yourlongstring);
# the above will solve any case sensitive issues
$country_names = array( Afghanistan , Bulgaria , United States , ...);
$country_count = array();
foreach ($country_names as $name) {
$occurances = substr_count($name, $yourtmplongstring );
$country_count[$name] = $occurances;
}
我希望,这是你所期待的!
我不认为你可以用一个电话这样做,但是,虽然你通过子公司重新开张,可能比预想的更快。